Finding the difference in time between the first and last file in a folder using bash

#!/bin/bash
# get the dates
start_date=$(date --utc --date "$(ls -Rt --full-time | tail -n1 | awk '{ print $6 }')" +%s)
end_date=$(date --utc --date "$(ls -Rt --full-time | head -n2 | tail -n1 | awk '{ print $6 }')" +%s)
 
# find the difference
difference=$((end_date-start_date))
 
# echo results
echo $end_date - $start_date = $difference seconds
echo $((difference/86400)) days

start_date=$(date --utc --date "$(ls -Rt --full-time | tail -n1 | awk '{ print $6 }')" +%s); end_date=$(date --utc --date "$(ls -Rt --full-time | head -n2 | tail -n1 | awk '{ print $6 }')" +%s); difference=$((end_date-start_date)); echo $end_date - $start_date = $difference seconds; echo $((difference/86400)) days;

map_1=nordiccastle;map_2=dance;start_date=$(date --utc --date "$(ls -Rt --full-time | tail -n1 | awk '{ print $6 }')" +%s); end_date=$(date --utc --date "$(ls -Rt --full-time | head -n2 | tail -n1 | awk '{ print $6 }')" +%s); difference=$((end_date-start_date)); echo $... Read Moreend_date - $start_date = $difference seconds; echo logs for $((difference/86400)) days; map_1_ended=$(find -name *00*.log | xargs egrep -A 4 "endmatch|timelimit -1" |grep $map_1 |wc -l); map_1_played=$(find -name *00*.log | xargs egrep "gamestart" |grep $map_1 |wc -l); echo $map_1 endmatched $map_1_ended out of $map_1_played times played; map_2_ended=$(find -name *00*.log | xargs egrep -A 4 "endmatch|timelimit -1" |grep $map_2 |wc -l); map_2_played=$(find -name *00*.log | xargs egrep "gamestart" |grep $map_2 |wc -l); echo $map_2 endmatched $map_2_ended out of $map_2_played times played